RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    For bcc structure of Na, crystal\[{{N}_{0}}=6\times {{10}^{23}},\]atomic weight of Na =23, radius\[=5\overset{o}{\mathop{\text{A}}}\,,\] then density will be

    A)  \[0.6\text{ }g/c{{m}^{3}}\]         

    B)  \[1.2\text{ }g/c{{m}^{3}}\]

    C)  \[0.4\text{ }g/c{{m}^{3}}\]         

    D)  \[1.0\text{ }g/c{{m}^{3}}\]

    Correct Answer: A

    Solution :

     Density\[(\rho )=\frac{ZM}{{{a}^{3}}{{N}_{0}}}\] \[=\frac{2\times 23}{{{(5\times {{10}^{-8}})}^{3}}\times 6\times {{10}^{23}}}\] \[=0.6g/c{{m}^{3}}\]


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