A) 1
B) 3
C) 2
D) 4
Correct Answer: D
Solution :
\[[{{H}^{+}}]=0.1m\,L\,M=0.1\times {{10}^{-3}}M={{10}^{-4}}M\] \[pH=-{{\log }_{10}}[{{H}^{+}}]=-\log [{{10}^{-4}}]\] \[=+4\]
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