A) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ COOH \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\]
B) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{C}}}\,-COOH\]
C) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ COOH \end{smallmatrix}}{\overset{\begin{smallmatrix} COOH \\ | \end{smallmatrix}}{\mathop{C}}}\,-H\]
D) \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ COOH \end{smallmatrix}}{\overset{\begin{smallmatrix} COOH \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}\]
Correct Answer: A
Solution :
\[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ COOH \end{smallmatrix}}{\overset{\begin{smallmatrix} Cl \\ | \end{smallmatrix}}{\mathop{{{C}^{*}}}}}\,-H\]shows optical isomerism because it contains asymmetrical carbon atom (C*)
You need to login to perform this action.
You will be redirected in
3 sec
