2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    The equation of wave is \[y=0.5\text{ }sin(101+x),\] This is moving along x-axis. Its velocity is

    A)  10 m/s           

    B)  20 m/s

    C)  5 m/s            

    D)  None of these

    Correct Answer: A

    Solution :

     \[y=0.5\sin (10t+x)\] The standard equation of travelling wave along the\[x-\]axis \[y=a\sin \left( \frac{2\pi t}{T}+\frac{2\pi x}{\lambda } \right)\] \[\frac{2\pi }{T}=2\pi n=10\] and \[\frac{2\pi }{\lambda }=1\] \[\therefore \] \[V=n\lambda =10m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner