question_answer

The gravitational force between the point masses m and M is F. Now if an another point mass 2m placed in front and touch of m, then force on M due to m and total force on M will be

A)  2F, F            

B)  F, 2F

C)  F, 3F            

D)  F, F

Correct Answer: C

Solution :

 \[F=\frac{GmM}{{{r}^{2}}}\] \[F'=\frac{G.(3m)M}{{{r}^{2}}}=3F\]