A) \[\frac{3{{\mu }_{0}}{{I}_{a}}}{4a}\]
B) \[\frac{{{\mu }_{0}}{{I}_{a}}}{4\pi a}(1+\pi )\]
C) \[\frac{{{\mu }_{0}}I}{4\pi a}\]
D) \[\frac{3{{\mu }_{0}}I}{8a}\]
Correct Answer: D
Solution :
The magnetic field due to radical arc \[B=\frac{{{\mu }_{0}}I\alpha }{4\pi a}\] \[=\frac{{{\mu }_{0}}I}{4\pi a}\left( \frac{3\pi }{2} \right)\] \[=\frac{3{{\mu }_{0}}I}{8a}\]
You need to login to perform this action.
You will be redirected in
3 sec
