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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    One mole (\[\gamma \]= 5/3) of monoatomic gas mixture and the one mole of diatomic gas (\[\gamma \]=7/5]. For mixtured the value of y will be

    A)  1.40             

    B)  1.50

    C)  1.53             

    D)  3.07

    Correct Answer: B

    Solution :

     For the mixture, \[\frac{{{n}_{1}}+{{n}_{2}}}{\gamma -1}=\frac{{{n}_{1}}}{{{\gamma }_{1}}-1}+\frac{{{n}_{2}}}{{{\gamma }_{2}}-1}\] \[\frac{1+1}{\gamma -1}=\frac{1}{\left( \frac{5}{3}-1 \right)}+\frac{1}{\left( \frac{7}{5}-1 \right)}\] \[\gamma =1.5\]


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