A) 8\[\Omega \]
B) 4\[\Omega \]
C) 2\[\Omega \]
D) 6\[\Omega \]
Correct Answer: A
Solution :
Suppose equivalent resistance of\[8\,\Omega \]and\[R\,\Omega \]is X. Then \[\frac{1}{X}=\frac{1}{8}+\frac{1}{R}\] \[X=\frac{8R}{8+R}\] \[\frac{2}{3}=\frac{X}{6}\] \[X=4\,\Omega \] \[\frac{8R}{8+R}=4\] \[R=8\,\Omega \]
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