A) \[\frac{k{{q}^{2}}}{a}[\sqrt{2}-4]\]
B) \[\frac{k{{q}^{2}}}{a}\]
C) \[0\]
D) \[\frac{kq}{a}[\sqrt{2}-4]\]
Correct Answer: A
Solution :
\[U=\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ -\frac{{{q}_{2}}}{a}-\frac{{{q}^{2}}}{a}-\frac{{{q}^{2}}}{a}-\frac{{{q}^{2}}}{a}+-\frac{{{q}^{2}}}{a\sqrt{2}}+\frac{{{q}^{2}}}{a\sqrt{2}} \right]\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\left[ \frac{\sqrt{2}{{q}^{2}}-4{{q}^{2}}}{a} \right]=\frac{k{{q}^{2}}}{a}(\sqrt{2}-4)\]
You need to login to perform this action.
You will be redirected in
3 sec
