2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2002

  • question_answer
    \[{{F}_{g}}\] and\[{{F}_{g}}\]represent the gravitational and electric forces between the electrons at distance 10 cm, then the ratio of \[\frac{{{F}_{g}}}{{{F}_{e}}}\] will be

    A)  \[{{10}^{42}}\]             

    B)  10

    C)  1                

    D)  \[{{10}^{-43}}\]

    Correct Answer: D

    Solution :

     \[\frac{{{F}_{g}}}{{{F}_{e}}}=\frac{G\frac{m.m}{{{r}^{2}}}}{\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}}=\frac{6.67\times {{10}^{-11}}\times (9.1\times {{10}^{-31}})}{9\times {{10}^{9}}\times {{(1.6\times {{10}^{-19}})}^{2}}}\] \[\approx {{10}^{-43}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner