A) 1/2
B) 1/4
C) 3/4
D) 2/3
Correct Answer: C
Solution :
Given, \[P(A)=\frac{1}{2},P(B)=\frac{1}{3},P(C)=\frac{1}{4}\] \[\therefore \] \[P(\overline{A})=1-\frac{1}{2}=\frac{1}{2}\] \[P(\overline{B})=1-\frac{1}{3}=\frac{2}{3}\] and \[P(\overline{C})=1-\frac{1}{4}=\frac{3}{4}\] Probability, that problem is not solved \[=P(\overline{A}).P(\overline{B}).P(\overline{C})\] \[=\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}\] \[=\frac{1}{4}\] \[\therefore \]Probability that the problem will be solved = 1 - (Probability that the problem's is not solved) \[=1-\frac{1}{4}\] \[=\frac{3}{4}\]
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