RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    \[\int{\sqrt{{{x}^{2}}+{{a}^{2}}}}dx\]is equal to

    A)  \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}+\frac{{{a}^{2}}}{2}\log \{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]

    B)  \[\frac{x}{2}\sqrt{{{x}^{2}}+{{a}^{2}}}-\frac{{{a}^{2}}}{2}\log \{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]

    C)  \[\frac{x}{2}+\sqrt{{{x}^{2}}+{{a}^{2}}}+\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]

    D)  \[\sqrt{{{x}^{2}}+{{a}^{2}}}+\frac{{{a}^{2}}}{2}\log \{x-\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]

    Correct Answer: A

    Solution :

     \[\int{\sqrt{{{x}^{2}}+{{a}^{2}}}}dx\] \[=\frac{1}{2}x\sqrt{{{x}^{2}}+{{a}^{2}}}+\frac{{{a}^{2}}}{2}\log \{x+\sqrt{{{x}^{2}}+{{a}^{2}}}\}+c\]


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