RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    The tangential point, where the line\[y=mx+c\]touches the parabola\[{{y}^{2}}=4ax,\]is

    A)  \[\left( \frac{a}{{{m}^{2}}},\frac{-2a}{m} \right)\]

    B)  \[\left( -\frac{a}{{{m}^{2}}},-\frac{2a}{m} \right)\]

    C)  \[\left( -\frac{a}{{{m}^{2}}},-\frac{2a}{m} \right)\]

    D)  \[\left( \frac{a}{{{m}^{2}}},\frac{2a}{m} \right)\]

    Correct Answer: A

    Solution :

     If the line\[y=mx+c,\]touches the parabola\[{{y}^{2}}=4\text{ }ax,\]then\[c=\frac{a}{m}\]and tangential point is\[\left( \frac{a}{{{m}^{2}}},\frac{-2a}{m} \right).\]


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