A) 16
B) \[-16\]
C) 32
D) \[-32\]
Correct Answer: C
Solution :
\[{{(1+i)}^{8}}+{{(1-i)}^{8}}=\{{{(1+i)}^{2}}\}+{{\{{{(1-i)}^{2}}\}}^{4}}\] \[={{\{1+2i-1\}}^{4}}+{{\{1-2i-1\}}^{4}}\] \[={{(2i)}^{4}}+{{(-2i)}^{4}}\] \[=16{{i}^{4}}+16{{i}^{4}}\] \[=16+16\] \[=32\]
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