RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    \[{{\cosh }^{-1}}x\]is equal to

    A)  \[\log (x+\sqrt{{{x}^{2}}+1})\]

    B)  \[\log (x+\sqrt{{{x}^{2}}-1})\]

    C)  \[\log (x+\sqrt{1-{{x}^{2}}})\]

    D)  \[\log (x-\sqrt{{{x}^{2}}-1})\]

    Correct Answer: B

    Solution :

     \[{{\cosh }^{-1}}x=\log (x+\sqrt{{{x}^{2}}-1})\]


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