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RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    \[2Cr{{(OH)}_{3}}+4O{{H}^{-}}+KI{{O}_{3}}\to 2CrO_{4}^{2-}\]\[+5{{H}_{2}}O+KI\] Equivalent weight of\[KI{{O}_{3}}\]in the above reaction is

    A)  molecular weight

    B)  \[\frac{molecular\text{ }weight}{3}\]

    C)  \[\frac{molecular\text{ }weight}{6}\]  

    D)  \[\frac{molecular\text{ }weight}{2}\]

    Correct Answer: C

    Solution :

     \[2Cr{{(OH)}_{3}}+4O{{H}^{-}}+\overset{+5}{\mathop{KI{{O}_{3}}}}\,\xrightarrow[{}]{{}}2CrO_{4}^{2-}\] \[+5{{H}_{2}}\text{O}+\overset{-1}{\mathop{KI}}\,\] In\[KI{{O}_{3}}\]change in the oxidation number of effective element\[(I)=+5-(-1)\] \[=6\] Equivalent weight of oxidising agent \[=\frac{molecular\text{ }weight}{change\text{ }in\text{ }oxidation\text{ }number\text{ }per\text{ }molecule}\] Equivalent weight of \[KI{{O}_{3}}=\frac{molecular\text{ }weight}{6}\]


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