A) \[1.2\times {{10}^{-2}}\]
B) \[1.2\times {{10}^{-4}}\]
C) \[72\times {{10}^{-2}}\]
D) \[72\times {{10}^{-4}}\]
Correct Answer: A
Solution :
For\[AgCl\] Solubility \[=\sqrt{{{K}_{sp}}}\] \[=\sqrt{1.44\times {{10}^{-4}}}\] \[=1.2\times {{10}^{-2}}\]
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