A) \[3.2\times {{10}^{-13}}cm\]
B) \[1.6\times {{10}^{-13}}cm\]
C) \[4.8\times {{10}^{-13}}cm\]
D) \[6.4\times {{10}^{-3}}cm\]
Correct Answer: C
Solution :
Nuclear radius\[=1.4\times {{10}^{-13}}\times {{(A)}^{1/2}}\] where, A = mass number \[=1.4\times {{10}^{-13}}\times {{(12)}^{1/2}}\] \[=4.8\times {{10}^{-13}}cm.\]
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