A) \[LiCl\]
B) \[L{{i}_{2}}O\]
C) \[LiAl{{H}_{4}}\]
D) \[Al{{H}_{3}}\]
Correct Answer: C
Solution :
\[LiAl{{H}_{4}}\]acts as strong reducing agent. \[4LiH+AlC{{l}_{3}}\xrightarrow[{}]{Ether}\underset{\begin{smallmatrix} lithium \\ aluminium \\ hydride \end{smallmatrix}}{\mathop{LiAl{{H}_{4}}}}\,+3LiCl\]
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