RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    The product will be obtained in the following reaction \[{{K}_{4}}[Fe{{(CN)}_{6}}]+{{O}_{3}}\xrightarrow[{}]{{{H}_{2}}O}\]Product

    A)  \[F{{e}^{2+}}\]ion

    B)  \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]

    C)  \[C{{N}^{-}}\]ion         

    D)  None of these

    Correct Answer: B

    Solution :

     \[\underset{\begin{smallmatrix}  potassium \\  ferrocyanide \end{smallmatrix}}{\mathop{2{{K}_{4}}[Fe{{(CN)}_{6}}+{{O}_{3}}}}\,\xrightarrow[{}]{{{H}_{2}}O}\] \[\underset{\begin{smallmatrix}  potassium \\  femcyanide \end{smallmatrix}}{\mathop{2{{K}_{3}}[Fe{{(CN)}_{6}}+2KOH}}\,+{{O}_{2}}]\]


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