RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    Radius of a soap bubble is increased from R to 2R, work done is this process in terms of surface tension is

    A)  \[24\pi {{R}^{2}}T\]         

    B)  \[12T\pi {{r}^{2}}\]

    C)  \[6T\pi {{r}^{2}}\]

    D)  \[4T\pi {{r}^{2}}\]

    Correct Answer: B

    Solution :

              \[W=T.\Delta A\] \[=T.[4\pi (2{{n}^{2}}-4\pi {{r}^{2}})]\] \[=12T\pi {{r}^{2}}\]


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