A) \[6.6\,\times \,{{10}^{-4}}C/{{m}^{3}}\]
B) \[6.6\,\times \,{{10}^{-5}}C/{{m}^{3}}\]
C) \[6.6\,\times \,{{10}^{-6}}C/{{m}^{3}}\]
D) None of these
Correct Answer: B
Solution :
In 1 s, the distance cover by beam of proton = velocity \[=3\times {{10}^{4}}m/s\] Charge, \[q={{10}^{-6}}C\] Charge density \[=\frac{Charge}{Volume}\] \[=\frac{Q}{Av}\] \[=\frac{{{10}^{-6}}}{3\times {{10}^{4}}\times 0.5\times {{10}^{-6}}}\] \[=6.6\times {{10}^{-5}}C/{{m}^{3}}\]
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