RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    When charge q enters perpendicular in magnetic field B, then frequency will be

    A)  \[\frac{2\pi m}{qB}\]

    B)  \[\frac{qB}{2\pi m}\]

    C)  \[\frac{qB}{\pi m}\]             

    D)  \[\frac{\pi m}{qB}\]

    Correct Answer: B

    Solution :

     \[R=\frac{mv}{Bq}\] Time period, \[T=\frac{2\pi R}{v}=\frac{2\pi m}{Bq}\] Frequency, \[n=\frac{1}{T}=\frac{Bq}{2\pi m}\]


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