RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    If\[{{C}_{air}}=10\]\[\mu \]F, then effective capacity will be

    A)  30\[\mu \]F           

    B)  15\[\mu \]F

    C)  3 \[\mu \]F            

    D)  10 \[\mu \]F

    Correct Answer: A

    Solution :

     \[{{C}_{air}}=\frac{{{\varepsilon }_{0}}A}{d}=10\,\mu F\] \[\therefore \] \[C={{C}_{1}}+{{C}_{2}}=\frac{{{K}_{1}}{{\varepsilon }_{2}}A/2}{d}+\frac{{{K}_{2}}{{\varepsilon }_{0}}A/2}{d}\] \[=\left( \frac{{{K}_{1}}+{{K}_{2}}}{2} \right)\frac{{{\varepsilon }_{0}}A}{d}\] \[=\left( \frac{2+4}{2} \right)\times 10=30\,\mu F\]


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