RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    To increase the frequency from 100 Hz to 400 Hz, the tension of string will be

    A)  4 times          

    B)  16 times

    C)  20 times         

    D)  None of these

    Correct Answer: B

    Solution :

     \[n\propto \sqrt{T}\] \[\therefore \] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{n_{1}^{2}}{n_{2}^{2}}={{\left( \frac{100}{400} \right)}^{2}}=\frac{1}{16}\] \[\Rightarrow \] \[{{T}_{2}}=16{{T}_{1}}\]


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