2. Solved Papers
  3. RAJASTHAN ­ PET

RAJASTHAN ­ PET Rajasthan PET Solved Paper-2001

  • question_answer
    If bullets of mass m strikes on a wall at the rate of 27 per second, then what will be the force applied on the wall?

    A)  mnv             

    B)  4mnv

    C)  2mnv

    D)  \[\frac{mnv}{2}\]

    Correct Answer: C

    Solution :

     Before collision, momentum of bullets = nmv After collision the momentum of bullets \[=2mnv\] Force on wall = the rate of change of momentum \[=\frac{2mnv}{1}\] \[=2mnv\]


You need to login to perform this action.
You will be redirected in 3 sec spinner