A) ethyl iodide
B) ethanol
C) iodoform
D) methyl iodide
Correct Answer: A
Solution :
Diethyl ether on heating with concentrated\[HI\]to give ethyl iodide. \[\underset{diethyl\,\,ether}{\mathop{{{C}_{2}}{{H}_{5}}-O-{{C}_{2}}{{H}_{5}}}}\,+2HI\xrightarrow{{}}\underset{ethyl\,\,iodide}{\mathop{2{{C}_{2}}{{H}_{5}}I}}\,+{{H}_{2}}O\]
You need to login to perform this action.
You will be redirected in
3 sec
