A) 1, 4-dibromo-2-butene
B) 1, 3-dibromo-1-butene
C) 3, 4-dibropio-2-butene
D) 2, 3-dibromo-2-butene
Correct Answer: A
Solution :
\[C{{H}_{2}}=CH-CH=C{{H}_{2}}\xrightarrow{B{{r}_{2}}}\] \[\underset{1,\,\,4-dibromobut-2-ne}{\mathop{BrC{{H}_{2}}CH=CHC{{H}_{2}}Br}}\,\]\[\underset{3,\,\,4-dibromo\,\,butene}{\mathop{+BrC{{H}_{2}}CHBrCH=C{{H}_{2}}}}\,\]
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