A) \[9\times {{10}^{9}}N{{c}^{2}}/{{m}^{2}}\]
B) \[8.9\times {{10}^{-12}}N{{m}^{2}}/{{C}^{2}}s\]
C) \[8.9\times {{10}^{-12}}{{C}^{2}}/N{{m}^{2}}\]
D) \[9\times {{10}^{9}}{{C}^{2}}/N{{m}^{2}}\]
Correct Answer: C
Solution :
Electric permittivity of free space \[{{\varepsilon }_{0}}=8.85\times {{10}^{-12}}{{C}^{2}}/N-{{m}^{2}}\] \[=8.9\times {{10}^{-12}}{{C}^{2}}/N-{{m}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
