A) Only\[Mn{{O}_{2}}\]
B) Only\[KMn{{O}_{4}}\]
C) Both\[Mn{{O}_{2}}\]and\[KMn{{O}_{4}}\]
D) Either\[Mn{{O}_{2}}\]or\[KMn{{O}_{4}}\]
Correct Answer: D
Solution :
From\[Mn{{O}_{2}}\], chlorine is obtained as \[Mn{{O}_{2}}+4HCl\xrightarrow{{}}MnC{{l}_{2}}+2{{H}_{2}}O+C{{l}_{2}}\] From\[KMn{{O}_{4}},\,\,C{{l}_{2}}\]is prepared as \[2KMn{{O}_{4}}+16HCl\xrightarrow{{}}\] \[2KCl+2MnC{{l}_{2}}+8{{H}_{2}}O+5C{{l}_{2}}\]
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