Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    Bulk modulus of water is\[2\times {{10}^{9}}N/{{m}^{2}}\]. The change in pressure required to increase the density of water by 0.1 % is

    A) \[2\times {{10}^{9}}N/{{m}^{2}}\]                           

    B) \[2\times {{10}^{8}}N/{{m}^{2}}\]

    C) \[2\times {{10}^{6}}N/{{m}^{2}}\]           

    D) \[2\times {{10}^{4}}N/{{m}^{2}}\]

    Correct Answer: C

    Solution :

    \[Mass=Volume\times density=Vd=constant\]                 \[V\Delta d+d\Delta V=0\]                 \[\frac{\Delta V}{V}=-\frac{\Delta d}{d}\]                 \[=-\frac{0.1}{100}={{10}^{-3}}\] Bulk modulus\[K=-\frac{\Delta p}{\Delta V/V}\]                 \[\Delta p=-K\frac{\Delta V}{V}\]                 \[\Delta p=2\times {{10}^{9}}\times {{10}^{-3}}\]                       \[=2\times {{10}^{6}}N/{{m}^{2}}\]


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