A) \[{{400}^{o}}C\]
B) \[{{300}^{o}}C\]
C) \[{{200}^{o}}C\]
D) \[{{100}^{o}}C\]
Correct Answer: A
Solution :
\[E=40\theta =\frac{{{\theta }^{2}}}{20}\] Differencing it w.r.t.,\[\theta \], we get \[\frac{dE}{d\theta }=40-\frac{2\theta }{20}\] At neutral temperature \[\theta ={{\theta }_{n}}-\frac{2{{\theta }_{n}}}{20}\] \[{{\theta }_{n}}={{400}^{o}}C\]
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