Punjab Medical Punjab - MET Solved Paper-2011

  • question_answer
    A body starts to fall freely under gravity. The distances covered by it in first, second and third seconds are in ratio

    A) \[1:3:5\]                              

    B) \[1:2:3\]

    C) \[1:4:9\]                              

    D) \[1:5:6\]

    Correct Answer: A

    Solution :

    According to equation of motion distance covered in nth second.                 \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\]                 \[{{S}_{n}}=\frac{a}{2}(2n-1)\]                   \[(\because \,\,u=0)\]                 \[\therefore {{s}_{1}}:{{s}_{2}}:{{s}_{3}}\] \[=\{2(1)-1\}:\{2(2)-1\}:\{2(3)-1\}\] \[=1:3:5\]


You need to login to perform this action.
You will be redirected in 3 sec spinner