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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    The reaction of\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]with\[NaCl\]and conc. \[{{H}_{2}}S{{O}_{4}}\]gives

    A) \[Cr{{O}_{2}}C{{l}_{2}}\]                              

    B) \[C{{r}_{2}}{{O}_{3}}\]

    C) \[CrC{{l}_{3}}\]                 

    D) \[CrOC{{l}_{2}}\]

    Correct Answer: A

    Solution :

    \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+4NaCl+6{{H}_{2}}S{{O}_{4}}\]\[\xrightarrow{{}}2KHS{{O}_{4}}+4NaHS{{O}_{4}}\]                \[\underset{chromyl\,\,chloride}{\mathop{+2Cr{{O}_{2}}C{{l}_{2}}}}\,+3{{H}_{2}}O\]


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