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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    Power supplied to a particle of mass \[2kg\] varies with time as\[P=3{{t}^{2}}/2\]watt, where t is in second. If velocity of particle at \[t=0\] is\[v=0,\]the velocity of particle at\[t=2s\]will be

    A) \[1m{{s}^{-1}}\]                               

    B) \[4m{{s}^{-1}}\]

    C) \[2m{{s}^{-1}}\]                               

    D) \[2\sqrt{2}m{{s}^{-1}}\]

    Correct Answer: C

    Solution :

    From work energy theorem,\[\Delta KE={{W}_{net}}\] \[{{K}_{fi}}-{{K}_{i}}=\int{P}\,\,dt\] \[\frac{1}{2}m{{v}^{2}}-0=\int_{0}^{2}{\left( \frac{3}{2}{{t}^{2}} \right)dt}\] \[\frac{1}{2}(2){{v}^{2}}=\frac{3}{2}\left[ \frac{{{t}^{3}}}{3} \right]_{0}^{2}=4\]


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