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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    A body of mass m is placed on the earths surface. It is taken from earths surface to a height\[h=3R\]. The change in gravitational potential energy of the body is

    A) \[\frac{2}{3}mgR\]                          

    B) \[\frac{3}{4}mgR\]

    C) \[\frac{mgR}{2}\]                            

    D) \[\frac{mgR}{4}\]

    Correct Answer: B

    Solution :

    The change in gravitational potential energy\[\Delta U=\frac{mgh}{1+\frac{h}{R}}=\frac{mg\times 3R}{1+\frac{3R}{R}}=\frac{3}{4}mgR\]


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