A) \[1.66\times {{10}^{5}}N{{C}^{-1}}\]
B) \[3.66\times {{10}^{5}}N{{C}^{-1}}\]
C) \[2.66\times {{10}^{-5}}N{{C}^{-1}}\]
D) \[2.66\times {{10}^{5}}N{{C}^{-1}}\]
Correct Answer: C
Solution :
The magnitude of the electric dipole moment is \[p=q\times 2l=(10\times {{10}^{-6}})\times (5.00\times {{10}^{-3}})\] \[=50\times {{10}^{-9}}cm\] The field is required at point far-away from the centre of the dipole. The electric field at an axial point (end-on position) distant\[r(=15cm)\]from the centre of the dipole is \[E=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{2p}{{{r}^{3}}}=(9.0\times {{10}^{9}})\frac{2\times (50\times {{10}^{-9}})}{{{(15\times {{10}^{-2}})}^{3}}}\]
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