A) the difference between the number of electrons in bonding and anti bonding orbitals
B) total number of electrons in bonding and anti bonding orbitals
C) twice the difference between the number of electrons in bonding and anti bonding orbitals
D) half the difference between number of electrons in bonding and anti bonding orbitals
Correct Answer: D
Solution :
Bond order\[=\frac{1}{2}({{N}_{b}}-{{N}_{a}})\]\[{{N}_{b}}=\]no. of electrons in bonding orbitals and,\[{{N}_{a}}=\]no. of electrons in antibonding orbitals.
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