A) \[{{56.46}^{o}}C\]
B) \[{{36.56}^{o}}C\]
C) \[{{56.14}^{o}}C\]
D) \[{{72.52}^{o}}C\]
Correct Answer: A
Solution :
We know that \[\Delta {{T}_{b}}=\frac{100{{k}_{b}}\times w}{W\times m}\] \[=\frac{100\times 17.2\times 0.456}{31.4\times 152}\] \[={{0.16}^{o}}C\] \[\therefore \]Boiling point of solution\[({{T}_{s}})={{T}^{o}}+\Delta {{T}_{b}}\] \[=56.30+0.16\] \[={{56.46}^{o}}C\]
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