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Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    The following diagram indicates the energy levels of a certain atom when the system moves from \[4E\] level to\[E\]. A photon of wavelength\[\lambda \], is emitted. The wavelength of photon produced during its transition from\[\frac{7}{3}E\] level to\[E\]is\[{{\lambda }_{2}}\]. The ratio\[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\]will be

    A) \[\frac{9}{4}\]

    B) \[\frac{4}{9}\]

    C) \[\frac{3}{2}\]

    D) \[\frac{7}{3}\]

    Correct Answer: B

    Solution :

    Transition from\[4E\]to\[E\]                 \[(4E-E)=\frac{hc}{{{\lambda }_{1}}}\Rightarrow {{\lambda }_{1}}=\frac{hc}{3E}\]             ... (i) Transition from\[\frac{7}{3}E\]to\[E\]                 \[\left( \frac{7}{3}E-E \right)=\frac{hc}{{{\lambda }_{2}}}\Rightarrow {{\lambda }_{2}}=\frac{3hc}{4E}\]  ? (ii) From Eq. (i) and (ii)                 \[\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{4}{9}\]


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