Punjab Medical Punjab - MET Solved Paper-2010

  • question_answer
    A circular thin disc of mass\[2kg\]has a diameter\[0.2m\]. Calculate its moment of inertia about an axis passing through the edge and perpendicular to the plane of the disc \[(in\text{ }kg-{{m}^{2}})\].

    A) \[0.01\]                               

    B) \[0.03\]

    C) \[0.02\]                               

    D) \[3\]

    Correct Answer: B

    Solution :

    Moment of inertia about an axis passing through centre of gravity and perpendicular to its plane,                 \[{{I}_{CM}}=\frac{1}{2}M{{R}^{2}}=\frac{1}{2}{{(0.1)}^{2}}\] About an axis passing through the edge                 \[I={{I}_{CM}}+M{{R}^{2}}\](Theorem of | | axis)                   \[=0.01+2\times {{(0.1)}^{2}}=0.03kg-{{m}^{2}}\]


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