Punjab Medical Punjab - MET Solved Paper-2009

  • question_answer
    Two acids\[A\]and\[B\]have\[P{{K}_{a}}4\]and\[6\], then

    A) \[A\] is \[4/6\] times stronger than\[B\]

    B) \[A\] is \[10\] times stronger than\[B\]

    C) \[A\] is \[6/4\] times stronger than\[B\]

    D) \[B\] is \[10\] times stronger than\[A\]

    Correct Answer: B

    Solution :

                        \[p{{K}_{a}}=\log {{K}_{a}}\] \[\therefore \]      \[{{(p{{K}_{a}})}_{A}}=-\log {{({{K}_{a}})}_{A}}\]                      \[{{({{K}_{a}})}_{A}}=\text{antilog}(-4)={{10}^{-4}}\] Similarly,   \[{{({{K}_{a}})}_{B}}=\text{antilog}(-6)={{10}^{-6}}\] \[\frac{Strength\,\,of\,\,A}{Strength\,\,of\,\,B}=\sqrt{\frac{{{K}_{a}}}{{{K}_{b}}}}\]                             \[=\sqrt{\frac{{{10}^{-4}}}{{{10}^{-6}}}}=10\] \[\therefore \]Strength of\[A=10\times \]strength of\[B\].


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