A) \[{{C}_{2}}{{H}_{5}}OH\]
B) \[{{C}_{2}}{{H}_{5}}I\]
C) \[C{{H}_{3}}CHO\]
D) \[CH{{I}_{3}}\]
Correct Answer: D
Solution :
\[C{{H}_{2}}=C{{H}_{2}}+HBr\xrightarrow{{}}C{{H}_{3}}\underset{X}{\mathop{-}}\,C{{H}_{2}}Br\] \[\underset{X}{\mathop{C{{H}_{3}}C{{H}_{2}}Br}}\,\xrightarrow[-KBr]{Aq.KOH}\underset{\begin{smallmatrix} ethyl\,\,alcohol \\ Y \end{smallmatrix}}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\] \[C{{H}_{3}}C{{H}_{2}}OH+N{{a}_{2}}C{{O}_{3}}+{{I}_{2}}\xrightarrow[(iodoform\,\,test)]{}\underset{\begin{smallmatrix} iodoform \\ Z \end{smallmatrix}}{\mathop{CH{{I}_{3}}}}\,\]\[+HCOONa+NaI+C{{O}_{2}}+{{H}_{2}}O\]
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