A) \[2.28\times {{10}^{-6}}T\]
B) \[1.679\times {{10}^{-6}}T\]
C) \[1.256\times {{10}^{-3}}T\]
D) \[1.572\times {{10}^{-5}}T\]
Correct Answer: C
Solution :
Number of turns in the coil,\[n=25\] Diameter of coil, \[d=10\text{ }cm\] \[=0.1m\] \[\therefore \]Radius, \[r=\frac{0.1}{2}=0.05m\] Current \[i=4A\] Hence, flux density of the coil at the centre is given by \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2\pi ni}{r}\] \[={{10}^{-7}}\times \frac{2\pi \times 25\times 4}{0.05}\] \[=1.256\times {{10}^{-3}}T\] \[(\because \,\,{{\mu }_{0}}=4\pi \times {{10}^{-7}}N{{A}^{-1}}{{m}^{-1}})\]
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