2. Solved Papers
  3. Punjab Medical

Punjab Medical Punjab - MET Solved Paper-2009

  • question_answer
    By what percent the energy of a satellite has to be increased to shift it from an orbit of radius\[r\]to\[\frac{3}{2}r\]?

    A) \[15%\]                               

    B) \[20.3%\]

    C) \[66.7%\]                            

    D) \[33.33%\]

    Correct Answer: D

    Solution :

    Binding energy of satellite in the first case is                 \[=\frac{GMm}{2\,\,r}\] where\[r\]is the radius of orbit. In second case\[BE=\frac{GMm}{2\times \frac{3r}{r}}\] \[\therefore \]  \[\Delta E=\frac{GMm}{r}\left( \frac{1}{2}-\frac{1}{3} \right)=\frac{GMm}{6r}\] \[%\]increase in energy of a satellite                        \[=\frac{\frac{GMm}{6r}}{\frac{GMm}{2r}}\times 100\]                 \[=\frac{2}{6}\times 100=33.33%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner