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Punjab Medical Punjab - MET Solved Paper-2009

  • question_answer
    The soave of a galvanometer of resistance\[100\Omega \]. contains 25 divisions. It gives a deflection of one division on passing a current of\[4\times {{10}^{-4}}A\]. The resistance in ohm to be added to it, so that it may become a voltmeter of range\[2.5V\]is

    A)  150     

    B)                         170

    C)  110                                       

    D)  220

    Correct Answer: A

    Solution :

    The deflection of one division of galvanometer is given by die current                     \[=4\times {{10}^{-4}}A\] or the current sensitivity of galvanometer is                     \[=4\times {{10}^{-4}}A/div\] \[\therefore \]  \[{{i}_{g}}=\]full scale deflection = current sensitivity\[\times \]total number of turns    \[=4\times {{10}^{-4}}\times 25={{10}^{-2}}A\] Resistance of galvanometer\[=100\Omega \] The value of resistance required,                 \[R=\frac{V}{{{i}_{g}}}-G=\frac{2.5}{{{10}^{-2}}}-100\]                    \[=250-100=150\Omega \]


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