Punjab Medical Punjab - MET Solved Paper-2008

  • question_answer
    Match list-I with list-II and select the correct answer using the code given below
    List I (successive IE) List II (Elements)
    \[I{{E}_{1}}\] \[I{{E}_{2}}\] \[I{{E}_{3}}\] \[(kJ\,mo{{l}^{-1}})\]
    1. 1320 - - A. H
    2. 520 7297 11810 B. Li
    3. 900 1758 14810 C. Be
    4. 800 2428 3660 D. B

    A) \[A-2,\,\,B-1,\,\,C-4,\,\,D-3\]

    B) \[A-3,\,\,B-4,\,\,C-2,\,\,D-1\]

    C) \[A-4,\,\,B-3,\,\,C-1,\,\,D-2\]    

    D) \[A-1,\,\,B-2,\,\,C-3,\,\,D-4\]

    Correct Answer: D

    Solution :

    Successive ionisation energies of the given elements are as follows
    \[I{{E}_{1}}\] \[I{{E}_{2}}\] \[I{{E}_{3}}\]
    H \[1{{s}^{2}}\] 1312.0 - -
    Li \[1{{s}^{2}},\,\,2{{s}^{1}}\] 518.0 7314 11810
    Be \[1{{s}^{2}},\,\,2{{s}^{2}}\] 899.9 1758 14810
    B \[1{{s}^{2}},\,\,2{{s}^{2}},\,\,2{{p}^{1}}\] 801 2460 3644


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