A) \[S{{c}^{3+}}\]
B) \[{{V}^{3+}}\]
C) \[T{{i}^{3+}}\]
D) \[C{{r}^{3+}}\]
Correct Answer: A
Solution :
The compound which have no unpaired electron forms colourless compound. So, \[S{{c}^{3+}}\xrightarrow{{}}3{{d}^{0}}\](no unpaired electron, colourless) \[{{V}^{3+}}\xrightarrow{{}}3{{d}^{2}}\](2 unpaired electrons, coloured) \[C{{r}^{3+}}\xrightarrow{{}}3{{d}^{2}}\](3 unpaired electrons, coloured) \[T{{i}^{3+}}\xrightarrow{{}}3{{d}^{1}}\](1 unpaired electrons, coloured)
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