Punjab Medical Punjab - MET Solved Paper-2008

  • question_answer
    \[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g)+22kcal\].  The activation energy for the forward reaction is 50 kcal. What is the activation energy for the backward reaction?

    A) \[-72kcal\]                          

    B) \[-28kcal\]

    C) \[+28kcal\]                         

    D) \[+72kcal\]

    Correct Answer: D

    Solution :

    \[{{N}_{2}}(g)+3{{H}_{2}}(g)2N{{H}_{3}}(g)+22kcal\] \[\because \]The activation energy for the forward reaction \[=50kcal\] \[\therefore \]The activation energy for the backward  reaction\[~=50+22\text{ }=72kcal\].


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