question_answer

A man slides down on a telegraphic pole with an acceleration equal to one-fourth of acceleration due to gravity. The frictional force between man and pole is equal to in terms of mans weight\[w\]

A) \[\frac{w}{4}\]                                 

B) \[\frac{w}{2}\]

C) \[\frac{3w}{4}\]                                               

D) \[w\]

Correct Answer: C

Solution :

Man is sliding down the telegraphic pole with acceleration\[g/4\]. So,                 \[mg-F=\frac{mg}{4}\] \[\Rightarrow \]               \[F=mg-\frac{mg}{4}\] \[\Rightarrow \]               \[F=\frac{3mg}{4}\] \[\Rightarrow \]               \[F=\frac{3w}{4}\]